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Austrian-Polish
1979 Austrian-Polish Competition
9
9
Part of
1979 Austrian-Polish Competition
Problems
(1)
greatest power of 2 that divides a_n = [(3+\sqrt{11} )^{2n+1}]
Source: Austrian Polish 1979 APMC
4/26/2020
Find the greatest power of
2
2
2
that divides
a
n
=
[
(
3
+
11
)
2
n
+
1
]
a_n = [(3+\sqrt{11} )^{2n+1}]
a
n
ā
=
[(
3
+
11
ā
)
2
n
+
1
]
, where
n
n
n
is a given positive integer.
floor function
power of 2
number theory