Let ABC be a triangle with incentre I. The angle bisectors AI, BI and CI meet [BC], [CA] and [AB] at D, E and F, respectively. The perpendicular bisector of [AD] intersects the lines BI and CI at M and N, respectively. Show that A, I, M and N lie on a circle. geometryincentercircumcircleperpendicular bisectorcyclic quadrilateralangle bisector