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Czech-Polish-Slovak Match
2014 Czech-Polish-Slovak Match
4
4
Part of
2014 Czech-Polish-Slovak Match
Problems
(1)
concurrent lines by a triangle ,a circle and 3 products
Source: Czech-Polish-Slovak Match 2014 day 2 P1
10/2/2017
Let
A
B
C
ABC
A
BC
be a triangle, and let
P
P
P
be the midpoint of
A
C
AC
A
C
. A circle intersects
A
P
,
C
P
,
B
C
,
A
B
AP, CP, BC, AB
A
P
,
CP
,
BC
,
A
B
sequentially at their inner points
K
,
L
,
M
,
N
K, L, M, N
K
,
L
,
M
,
N
. Let
S
S
S
be the midpoint of
K
L
KL
K
L
. Let also
2
⋅
∣
A
N
∣
⋅
∣
A
B
∣
⋅
∣
C
L
∣
=
2
⋅
∣
C
M
∣
⋅
∣
B
C
∣
⋅
∣
A
K
∣
=
∣
A
C
∣
⋅
∣
A
K
∣
⋅
∣
C
L
∣
.
2 \cdot | AN |\cdot |AB |\cdot |CL | = 2 \cdot | CM | \cdot| BC | \cdot| AK| = | AC | \cdot| AK |\cdot |CL |.
2
⋅
∣
A
N
∣
⋅
∣
A
B
∣
⋅
∣
C
L
∣
=
2
⋅
∣
CM
∣
⋅
∣
BC
∣
⋅
∣
A
K
∣
=
∣
A
C
∣
⋅
∣
A
K
∣
⋅
∣
C
L
∣.
Prove that if
P
≠
S
P\ne S
P
=
S
, then the intersection of
K
N
KN
K
N
and
M
L
ML
M
L
lies on the perpendicular bisector of the
P
S
PS
PS
. (Jan Mazák)
geometry
concurrent