MathDB

1

Part of 2005 Danube Mathematical Olympiad

Problems(1)

4x^3 - 3x + 1 = 2y^2 has at least 31 solutions

Source: Donova MO 2005, problem 1

2/11/2006
Prove that the equation 4x3−3x+1=2y24x^3-3x+1=2y^2 has at least 3131 solutions in positive integers xx and yy with x≤2005x\leq 2005.
trigonometrynumber theory proposednumber theory