Let Ar,Br,Cr be points on the circumference of a given circle S. From the triangle ArBrCr, called Δr, the triangle Δr+1 is obtained by constructing the points Ar+1,Br+1,Cr+1on S such that Ar+1Ar is parallel to BrCr, Br+1Br is parallel to CrAr, and Cr+1Cr is parallel to ArBr. Each angle of Δ1 is an integer number of degrees and those integers are not multiples of 45. Prove that at least two of the triangles Δ1,Δ2,…,Δ15 are congruent. geometrycircleTrianglecongruent trianglesIMO Shortlist