A point M is chosen on the side AC of the triangle ABC in such a way that the radii of the circles inscribed in the triangles ABM and BMC are equal. Prove that
BM^{2} \equal{} X \cot \left( \frac {B}{2}\right)
where X is the area of triangle ABC. geometryinradiustrigonometryarea of a triangleIMO Shortlist