6
Part of 2007 IMO Shortlist
Problems(3)
a^2_1 + a^2_2 + ... + a^2_100 = 1
Source: IMO Shortlist 2007, A6, AIMO 2008, TST 7, P1
7/13/2008
Let be nonnegative real numbers such that a^2_1 \plus{} a^2_2 \plus{} \ldots \plus{} a^2_{100} \equal{} 1. Prove that
a^2_1 \cdot a_2 \plus{} a^2_2 \cdot a_3 \plus{} \ldots \plus{} a^2_{100} \cdot a_1 < \frac {12}{25}.
Author: Marcin Kuzma, Poland
inequalitiesIMO Shortlist
Find the smallest positive real number
Source: IMO Shortlist 2007, G6 / USA TST 2008, Day 2, Problem 6
7/13/2008
Determine the smallest positive real number with the following property. Let be a convex quadrilateral, and let points , , , and lie on sides , , , and , respectively. Consider the areas of triangles , , and ; let be the sum of the two smallest ones, and let be the area of quadrilateral . Then we always have .Author: Zuming Feng and Oleg Golberg, USA
geometrycircumcirclesymmetryratioIMO Shortlist
Select an easier sub-problem and you get an IMO problem
Source: IMO Shortlist 2007, N6
7/13/2008
Let be a positive integer. Prove that the number (4 \cdot k^2 \minus{} 1)^2 has a positive divisor of the form 8kn \minus{} 1 if and only if is even.
[url=http://www.mathlinks.ro/viewtopic.php?p=894656#894656]Actual IMO 2007 Problem, posed as question 5 in the contest, which was used as a lemma in the official solutions for problem N6 as shown above.
Author: Kevin Buzzard and Edward Crane, United Kingdom
quadraticsnumber theoryIMOIMO 2007Vieta JumpingDivisibility