5
Part of 2011 IMO Shortlist
Problems(3)
IMO Shortlist 2011, Algebra 5
Source: IMO Shortlist 2011, Algebra 5
7/11/2012
Prove that for every positive integer the set can be partitioned into triples in such a way that the numbers from each triple are the lengths of the sides of some obtuse triangle.Proposed by Canada
trigonometryinequalitiestriangle inequalityalgebraTriangleIMO Shortlist
IMO Shortlist 2011, Combinatorics 5
Source: IMO Shortlist 2011, Combinatorics 5
7/12/2012
Let be a positive integer, and consider a checkerboard consisting of unit squares. At the centre of some of these unit squares there is an ant. At time , each ant starts moving with speed parallel to some edge of the checkerboard. When two ants moving in the opposite directions meet, they both turn clockwise and continue moving with speed . When more than ants meet, or when two ants moving in perpendicular directions meet, the ants continue moving in the same direction as before they met. When an ant reaches one of the edges of the checkerboard, it falls off and will not re-appear.Considering all possible starting positions, determine the latest possible moment at which the last ant falls off the checkerboard, or prove that such a moment does not necessarily exist.Proposed by Toomas Krips, Estonia
combinatoricsIMO ShortlistalgorithmHi
IMO Shortlist 2011, G5
Source: IMO Shortlist 2011, G5
7/13/2012
Let be a triangle with incentre and circumcircle . Let and be the second intersection points of with and , respectively. The chord meets at a point , and at a point . Let be the intersection point of the line through parallel to and the line through parallel to . Suppose that the tangents to at and meet at a point . Prove that the three lines and are either parallel or concurrent.Proposed by Irena Majcen and Kris Stopar, Slovenia
geometryincentercircumcirclegeometric transformationhomothetyIMO Shortlist