Let ABC be an acute triangle with AB=AC. The incircle ω of the triangle touches the sides BC,CA and AB at D,E and F, respectively. The perpendicular line erected at C onto BC meets EF at M, and similarly the perpendicular line erected at B onto BC meets EF at N. The line DM meets ω again in P, and the line DN meets ω again at Q. Prove that DP=DQ. Ruben Dario & Leo Giugiuc (Romania) geometryJBMOsimilar trianglesincircle