Subcontests
(25)Cryptic Problem
Let b≥3 be a positive integer and let σ be a nonidentity permutation of the set {0,1,…,b−1} such that σ(0)=0. The substitution cipher Cσ encrypts every positive integer n by replacing each digit a in the representation of n in base b with σ(a). Let d be any positive integer such that b does not divide d. We say that Cσ complies with d if Cσ maps every multiple of d onto a multiple of d, and we say that d is cryptic if there exists some Cσ such that Cσ complies with d.Let k be any positive integer, and let p=2k+1.a) Find the greatest power of 2 that is cryptic in base 2p, and prove that there is only one substitution cipher complying with it.b) Find the greatest power of p that is cryptic in base 2p, and prove that there is only one substitution cipher complying with it.c) Suppose, furthermore, that p is a prime number. Find the greatest cryptic positive integer in base 2p and prove that there is only one substitution cipher that complies with it.Proposed by Nikolai Beluhov, Bulgaria Feuerbach Circle
In a quadrilateral ABCD, AB=BC=DA/2, and ∠ABC is a right angle. The midpoint of BC is E, the orthogonal projection of C on AD is F, and the orthogonal projection of B on CD is G. The second intersection point of circle (BCF) (with center H) and line BG is K, and the second intersection point of circle (BCF) and line HK is L. The intersection of lines BL and CF is M. The center of the Feurbach circle of triangle BFM is N. Prove that ∠BNE is a right angle.Proposed by Zsombor Fehér, Cambridge Problem of Number Theory
Find all triples (a,b,c) of distinct positive integers so that there exists a subset S of the positive integers for which for all positive integers n exactly one element of the triple (an,bn,cn) is in S.Proposed by Carl Schildkraut, MIT Circumcenter, incentre and Simson-Wallace line
Let O be the circumcenter of triangle ABC, and D be an arbitrary point on the circumcircle of ABC. Let points X,Y and Z be the orthogonal projections of point D onto lines OA,OB and OC, respectively. Prove that the incenter of triangle XYZ is on the Simson-Wallace line of triangle ABC corresponding to point D. The magic trick
An illusionist and his assistant are about to perform the following magic trick.Let k be a positive integer. A spectator is given n=k!+k−1 balls numbered 1,2,…,n. Unseen by the illusionist, the spectator arranges the balls into a sequence as he sees fit. The assistant studies the sequence, chooses some block of k consecutive balls, and covers them under her scarf. Then the illusionist looks at the newly obscured sequence and guesses the precise order of the k balls he does not see.Devise a strategy for the illusionist and the assistant to follow so that the trick always works.(The strategy needs to be constructed explicitly. For instance, it should be possible to implement the strategy, as described by the solver, in the form of a computer program that takes k and the obscured sequence as input and then runs in time polynomial in n. A mere proof that an appropriate strategy exists does not qualify as a complete solution.) Game on [2^n-1] and [2^{n+1}-1]
For every n non-negative integer let S(n) denote a subset of the positive integers, for which i is an element of S(n) if and only if the i-th digit (from the right) in the base two representation of n is a digit 1.Two players, A and B play the following game: first, A chooses a positive integer k, then B chooses a positive integer n for which 2n⩾k. Let X denote the set of integers {0,1,…,2n−1}, let Y denote the set of integers {0,1,…,2n+1−1}. The game consists of k rounds, and in each round player A chooses an element of set X or Y, then player B chooses an element from the other set. For 1⩽i⩽k let xi denote the element chosen from set X, let yi denote the element chosen from set Y.Player B wins the game, if for every 1⩽i⩽k and 1⩽j⩽k, xi<xj if and only if yi<yj and S(xi)⊂S(xj) if and only if S(yi)⊂S(yj). Which player has a winning strategy?Proposed by Levente Bodnár, Cambridge Symmetric Polygon into a Square
Prove that every polygon that has a center of symmetry can be dissected into a square such that it is divided into finitely many polygonal pieces, and all the pieces can only be translated. (In other words, the original polygon can be divided into polygons A1,A2,…,An, a square can be divided into polygons a B1,B2,…,Bn such that for 1⩽i⩽n polygon Bi is a translated copy of polygon Ai.)