Problems(1)
Let Ω be the circumcircle of the triangle ABC. The points Ma,Mb and Mc are the midpoints of the sides BC,CA and AB, respectively. Let Al,Bl and Cl be the intersection points of Ω with the rays McMb,MaMc and MbMa respectively. Similarly, let Ar,Br and Cr be the intersection points of Ω with the rays MbMc,McMa and MaMb respectively. Prove that the mean of the areas of the triangles AlBlCl and ArBrCr is not less than the area of the triangle ABC.Proposed by L. Shatunov and T. Kazantseva Kvantgeometryareas