Let ABC be an equiangular triangle with circumcircle ω. Let point F∈AB and point E∈AC so that ∠ABE+∠ACF=60∘. The circumcircle of triangle AFE intersects the circle ω in the point D. The halflines DE and DF intersect the line through B and C in the points X and Y. Prove that the incenter of the triangle DXY is independent of the choice of E and F.(The angles in the problem statement are not directed. It is assumed that E and F are chosen in such a way that the halflines DE and DF indeed intersect the line through B and C.) geometryincenterEquilateralFixed pointfixed