Let BM be a median in an acute-angled triangle ABC. A point K is chosen on the line through C tangent to the circumcircle of △BMC so that ∠KBC=90∘. The segments AK and BM meet at J. Prove that the circumcenter of △BJK lies on the line AC.Aleksandr Kuznetsov, Russia geometrycircumcircleCircumcentermedian