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Tournament Of Towns
1986 Tournament Of Towns
(116) 4
(116) 4
Part of
1986 Tournament Of Towns
Problems
(1)
TOT 116 1986 Spring S4 F(x+1)F(x)+F(x+1)+1=0, F not continuous
Source:
8/29/2019
The function
F
F
F
, defined on the entire real line, satisfies the following relation (for all
x
x
x
) :
F
(
x
+
1
)
F
(
x
)
+
F
(
x
+
1
)
+
1
=
0
F(x +1 )F(x) + F(x + 1 ) + 1 = 0
F
(
x
+
1
)
F
(
x
)
+
F
(
x
+
1
)
+
1
=
0
. Prove that
F
F
F
is not continuous.(A.I. Plotkin, Leningrad)
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