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International Contests
Tournament Of Towns
1990 Tournament Of Towns
(271) 5
(271) 5
Part of
1990 Tournament Of Towns
Problems
(1)
TOT 271 1990 Autumn A J5 x_{n+1}=|x_n|-x_{n-1} has period 9
Source:
6/8/2024
The numerical sequence
{
x
n
}
\{x_n\}
{
x
n
}
satisfies the condition
x
n
+
1
=
∣
x
n
∣
−
x
n
−
1
x_{n+1}=|x_n|-x_{n-1}
x
n
+
1
=
∣
x
n
∣
−
x
n
−
1
for all
n
>
1
n > 1
n
>
1
. Prove that the sequence is periodic with period
9
9
9
, i.e. for any
n
>
1
n > 1
n
>
1
we have
x
n
=
x
n
+
9
x_n = x_{n+9}
x
n
=
x
n
+
9
.(M Kontsevich, Moscow)
algebra
periodic
Sequence
recurrence relation