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Tournament Of Towns
1991 Tournament Of Towns
(300) 1
(300) 1
Part of
1991 Tournament Of Towns
Problems
(1)
TOT 300 1991 Autumn O J1 AB= BC wanted, 2 circles
Source:
6/9/2024
The centre of circle
1
1
1
lies on circle
2
2
2
.
A
A
A
and
B
B
B
are the intersection points of the circles. The tangent line to circle
2
2
2
at point
B
B
B
intersects circle
1
1
1
at point
C
C
C
. Prove that
A
B
=
B
C
AB = BC
A
B
=
BC
.(V. Prasovov, Moscow)
geometry
equal segments
isosceles