(533) 5

Part of 1997 Tournament Of Towns

Problems(1)

TOT 533 1997 Spring J A5 1997^{17} not sum of perfect squares

Source:

Prove that the number
(a)

97^{97}

1997^{17}

cannot be equal to a sum of cubes of several consecutive integers.
(AA Egorov)

number theoryperfect cubeconsecutive