2
Part of 2019 Tournament Of Towns
Problems(6)
Combinatorics(pretty hard,pls help)
Source: Tournament of towns
3/13/2019
Consider 2n+1 coins lying in a circle. At the beginning, all the coins are heads up. Moving clockwise, 2n+1 flips are performed: one coin is flipped, the next coin is skipped, the next coin is flipped, the next two coins are skipped, the next coin is flipped,the next three coins are skipped and so on, until finally 2n coins are skipped and the next coin is flipped.Prove that at the end of this procedure,exactly one coin is heads down.
combinatoricsInvariantscoinscombinatorics unsolvedCircular array
a^{n+1} + b^{n+1} is divisible by a^n + b^n for infinitely n
Source: Tournament of Towns, Senior O-Level , Spring 2019 p2
5/11/2020
Consider two positive integers and such that is divisible by for infinitely many positive integers . Is it necessarily true that ?(Boris Frenkin)
number theorySum of powersDivisibility
position of orthocenter of OXY does not depend on the choice of P on circle
Source: Tournament of Towns, Junior O-Level , Fall 2019 p2
4/19/2020
Let be a circle with the center and and be two different points on . For any third point of the circle let and be the midpoints of the segments and . Finally, let be the orthocenter (the point of intersection of the altitudes) of the triangle . Prove that the position of the point H does not depend on the choice of .(Artemiy Sokolov)
geometryFixed pointfixedorthocentercircle
S/(AB + AC)> S_1/(A_1B_1 + A_1C_1), area triangle inequality
Source: Tournament of Towns, Junior A-Level , Fall 2019 p2
4/19/2020
Two acute triangles and are such that and lie on , and lies inside the triangle . Let and be the areas of those triangles respectively. Prove that (Nairi Sedrakyan, Ilya Bogdanov)
geometrygeometric inequalityarea of a triangletriangle inequalityinequalities
Easy geom to solve
Source: International Mathematical Tournament of towns
12/2/2019
Given a convex pentagon such that is parallel to and . Angle bisectors of angles and intersect at . Prove that and are parallel.
geometryangle bisector
P is orthocenter of acute ABC, 3 equal chords given
Source: Tournament of Towns, Senior A-Level , Fall 2019 p2
4/18/2020
Let be an acute triangle. Suppose the points lie on its sides respectively and the segments intersect in a common point inside the triangle. For each of those segments let us consider the circle such that the segment is its diameter, and the chord of this circle that contains the point and is perpendicular to this diameter. All three these chords occurred to have the same length. Prove that is the orthocenter of the triangle .(Grigory Galperin)
orthocentergeometryChordsequal segments