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Albania Team Selection Test
2010 Albania Team Selection Test
2010 Albania Team Selection Test
Part of
Albania Team Selection Test
Subcontests
(5)
5
1
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Albanian IMO TST 2010 Question 5
a) Let's consider a finite number of big circles of a sphere that do not pass all from a point. Show that there exists such a point that is found only in two of the circles. (With big circle we understand the circles with radius equal to the radius of the sphere.) b) Using the result of part
a
)
a)
a
)
show that, for a set of
n
n
n
points in a plane, that are not all in a line, there exists a line that passes through only two points of the given set.
4
1
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Albanian IMO TST 2010 Question 4
With
σ
(
n
)
\sigma (n)
σ
(
n
)
we denote the sum of natural divisors of the natural number
n
n
n
. Prove that, if
n
n
n
is the product of different prime numbers of the form
2
k
−
1
2^k-1
2
k
−
1
for
k
∈
N
k \in \mathbb{N}
k
∈
N
(
M
e
r
s
e
n
n
e
′
s
Mersenne's
M
erse
nn
e
′
s
prime numbers) , than
σ
(
n
)
=
2
m
\sigma (n)=2^m
σ
(
n
)
=
2
m
, for some
m
∈
N
m \in \mathbb{N}
m
∈
N
. Is the inverse statement true?
3
1
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Albanian IMO TST 2010 Question 3
One point of the plane is called
r
a
t
i
o
n
a
l
rational
r
a
t
i
o
na
l
if both coordinates are rational and
i
r
r
a
t
i
o
n
a
l
irrational
i
rr
a
t
i
o
na
l
if both coordinates are irrational. Check whether the following statements are true or false: a) Every point of the plane is in a line that can be defined by
2
2
2
rational points. b) Every point of the plane is in a line that can be defined by
2
2
2
irrational points.This maybe is not algebra so sorry if I putted it in the wrong category!
2
1
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Albanian IMO TST 2010 Question 2
Find all the continuous functions
f
:
R
↦
R
f : \mathbb{R} \mapsto\mathbb{R}
f
:
R
↦
R
such that
∀
x
,
y
∈
R
\forall x,y \in \mathbb{R}
∀
x
,
y
∈
R
,
(
1
+
f
(
x
)
f
(
y
)
)
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
(1+f(x)f(y))f(x+y)=f(x)+f(y)
(
1
+
f
(
x
)
f
(
y
))
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
.
1
1
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Albanian IMO TST 2010 Question 1
A
B
C
ABC
A
BC
is an acute angle triangle such that
A
B
>
A
C
AB>AC
A
B
>
A
C
and
B
A
C
^
=
6
0
∘
\hat{BAC}=60^{\circ}
B
A
C
^
=
6
0
∘
. Let's denote by
O
O
O
the center of the circumscribed circle of the triangle and
H
H
H
the intersection of altitudes of this triangle. Line
O
H
OH
O
H
intersects
A
B
AB
A
B
in point
P
P
P
and
A
C
AC
A
C
in point
Q
Q
Q
. Find the value of the ration
P
O
H
Q
\frac{PO}{HQ}
H
Q
PO
.