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Austrian MO Beginners' Competition
2003 Austria Beginners' Competition
2
2
Part of
2003 Austria Beginners' Competition
Problems
(1)
(x -4) (x^2 - 8x + 14)^2 = (x - 4)^3
Source: 2003 Austria Beginners' Competition p2
10/4/2022
Find all real solutions of the equation
(
x
−
4
)
(
x
2
−
8
x
+
14
)
2
=
(
x
−
4
)
3
(x -4) (x^2 - 8x + 14)^2 = (x - 4)^3
(
x
−
4
)
(
x
2
−
8
x
+
14
)
2
=
(
x
−
4
)
3
.
algebra