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1

Part of 2006 Austria Beginners' Competition

Problems(1)

a^{2006} + b^{2006} + 1 is divisible by 2006^2

Source: 2006 Austria Beginners' Competition p1

10/12/2022
Do integers a,ba, b exist such that a2006+b2006+1a^{2006} + b^{2006} + 1 is divisible by 200622006^2?
number theorydivisible