In a non isosceles triangle ABC let w be the angle bisector of the exterior angle at C. Let D be the point of intersection of w with the extension of AB. Let kA be the circumcircle of the triangle ADC and analogy kB the circumcircle of the triangle BDC. Let tA be the tangent line to kA in A and tB the tangent line to kB in B. Let P be the point of intersection of tA and tB.
Given are the points A and B. Determine the set of points P\equal{}P(C ) over all points C, so that ABC is a non isosceles, acute-angled triangle. geometrycircumcircleangle bisectorexterior anglegeometry unsolved