MathDB

Problems(4)

Angle bissector

Source: French TST 2004 pb.2; German contest (Bundeswettbewerb) 2003, 1st round

5/25/2004
Let ABCDABCD be a parallelogram. Let MM be a point on the side ABAB and NN be a point on the side BCBC such that the segments AMAM and CNCN have equal lengths and are non-zero. The lines ANAN and CMCM meet at QQ. Prove that the line DQDQ is the bisector of the angle ADC\measuredangle ADC. Alternative formulation. Let ABCDABCD be a parallelogram. Let MM and NN be points on the sides ABAB and BCBC, respectively, such that AM=CN0AM=CN\neq 0. The lines ANAN and CMCM intersect at a point QQ. Prove that the point QQ lies on the bisector of the angle ADC\measuredangle ADC.
trigonometrygeometryangle bisectorgeometry proposed
Regional Olympiad - FBH 2014 Grade 9 Problem 3

Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2014

9/24/2018
In triangle ABCABC (bc)(b \geq c), point EE is the midpoint of shorter arc BCBC. If DD is the point such that EDED is the diameter of circumcircle ABCABC, prove that DEA=12(βγ)\angle DEA = \frac{1}{2}(\beta-\gamma)
geometrycircumcircle
Regional Olympiad - FBH 2014 Grade 11 Problem 3

Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2014

9/24/2018
Excircle of triangle ABCABC to side ABAB of triangle ABCABC touches side ABAB in point DD. Determine ratio AD:BDAD : BD if CAB=2ADC\angle CAB = 2 \angle ADC
ratiogeometryexcircle
Regional Olympiad - FBH 2014 Grade 12 Problem 3

Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2014

9/24/2018
Find all integers nn such that n48n+15n^4-8n+15 is product of two consecutive integers
consecutivenumber theory