In a triangle △ABC, let ha,hb and hc the atlitudes. Let D be the point where the inner bisector of ∠BAC cuts to the side BC and da is the distance from the D point next to AB. The distances db and dc are similarly defined. Show that:
23≤hada+hbdb+hcdc
For what kind of triangles does the equality hold? geometrygeometric inequalityangle bisectordistance