In △ABC, ∠BAC=60∘, point D lies on side BC, O1 and O2 are the centers of the circumcircles of △ABD and △ACD, respectively. Lines BO1 and CO2 intersect at point P. If I is the incenter of △ABC and H is the orthocenter of △PBC, then prove that the four points B,C,I,H are on the same circle.
geometryincenterorthocentergeometry solvedCircumcentercyclic quadrilateralSpiral Similarity