As shown in the figure, given △ABC with AB⊥AC, AB=BC, D is the midpoint of the side AB, DF⊥DE, DE=DF and BE⊥EC. Prove that ∠AFD=∠CEF.
https://cdn.artofproblemsolving.com/attachments/9/2/f16a8c8c463874f3ccb333d91cdef913c34189.png geometryisosceles right triangleequal angles