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France Contests
French Mathematical Olympiad
1993 French Mathematical Olympiad
Problem 1
Problem 1
Part of
1993 French Mathematical Olympiad
Problems
(1)
measuring with set of weights
Source: France 1993 P1
5/12/2021
Assume we are given a set of weights,
x
1
x_1
x
1
of which have mass
d
1
d_1
d
1
,
x
2
x_2
x
2
have mass
d
2
d_2
d
2
, etc,
x
k
x_k
x
k
have mass
d
k
d_k
d
k
, where
x
i
,
d
i
x_i,d_i
x
i
,
d
i
are positive integers and
1
≤
d
1
<
d
2
<
…
<
d
k
1\le d_1<d_2<\ldots<d_k
1
≤
d
1
<
d
2
<
…
<
d
k
. Let us denote their total sum by
n
=
x
1
d
1
+
…
+
x
k
d
k
n=x_1d_1+\ldots+x_kd_k
n
=
x
1
d
1
+
…
+
x
k
d
k
. We call such a set of weights perfect if each mass
0
,
1
,
…
,
n
0,1,\ldots,n
0
,
1
,
…
,
n
can be uniquely obtained using these weights.(a) Write down all sets of weights of total mass
5
5
5
. Which of them are perfect? (b) Show that a perfect set of weights satisfies
(
1
+
x
1
)
(
1
+
x
2
)
⋯
(
1
+
x
k
)
=
n
+
1.
(1+x_1)(1+x_2)\cdots(1+x_k)=n+1.
(
1
+
x
1
)
(
1
+
x
2
)
⋯
(
1
+
x
k
)
=
n
+
1.
(c) Conversely, if
(
1
+
x
1
)
(
1
+
x
2
)
⋯
(
1
+
x
k
)
=
n
+
1
(1+x_1)(1+x_2)\cdots(1+x_k)=n+1
(
1
+
x
1
)
(
1
+
x
2
)
⋯
(
1
+
x
k
)
=
n
+
1
, prove that one can uniquely choose the corresponding masses
d
1
,
d
2
,
…
,
d
k
d_1,d_2,\ldots,d_k
d
1
,
d
2
,
…
,
d
k
with
1
≤
d
1
<
…
<
d
k
1\le d_1<\ldots<d_k
1
≤
d
1
<
…
<
d
k
in order for the obtained set of weights is perfect. (d) Determine all perfect sets of weights of total mass
1993
1993
1993
.
number theory