MathDB

1

Part of 1958 Kurschak Competition

Problems(1)

ontruse triangle with angles 120^o anomg 6 points

Source: 1958 Hungary - Kürschák Competition p1

10/10/2022
Given any six points in the plane, no three collinear, show that we can always find three which form an obtuse-angled triangle with one angle at least 120o120^o.
combinatoricscombinatorial geometryobtuse