MathDB

3

Part of 1958 Kurschak Competition

Problems(1)

(ACE)=(BDF) if ABCDEF is convex with oppoite sides //

Source: 1958 Hungary - Kürschák Competition p3

10/10/2022
The hexagon ABCDEFABCDEF is convex and opposite sides are parallel. Show that the triangles ACEACE and BDFBDF have equal area
geometryhexagonequal areas