3

Part of 1962 Kurschak Competition

Problems(1)

1of DA, DB, DC exceeds 1 of PA, PB and PC, tetrahedron ABCD

Source: 1962 Hungary - Kürschák Competition p3

P

is any point of the tetrahedron

ABCD

D

. Show that at least one of the three distances

DA

DB

DC

exceeds at least one of the distances

PA

PB

PC

geometry3D geometrytetrahedronGeometric Inequalities