MathDB

Problems(6)

Lattice

Source: Iranian National Olympiad (3rd Round) 2006

8/26/2006
LL is a fullrank lattice in R2\mathbb R^{2} and KK is a sub-lattice of LL, that A(K)A(L)=m\frac{A(K)}{A(L)}=m. If mm is the least number that for each xLx\in L, mxmx is in KK. Prove that there exists a basis {x1,x2}\{x_{1},x_{2}\} for LL that {x1,mx2}\{x_{1},mx_{2}\} is a basis for KK.
abstract algebragroup theorycalculusintegrationinvariantnumber theory proposednumber theory
Find x,y,z

Source: Iranian National Olympiad (3rd Round) 2006

9/19/2006
Find all real x,y,zx,y,z that {x+y+zx=12y+z+xy=12z+x+yz=12\left\{\begin{array}{c}x+y+zx=\frac12\\ \\ y+z+xy=\frac12\\ \\ z+x+yz=\frac12\end{array}\right.
algebrapolynomialalgebra proposed
Inner product

Source: Iranian National Olympiad (3rd Round) 2006

9/21/2006
Suppose (u,v)(u,v) is an inner product on Rn\mathbb R^{n} and f:RnRnf: \mathbb R^{n}\longrightarrow\mathbb R^{n} is an isometry, that f(0)=0f(0)=0. 1) Prove that for each u,vu,v we have (u,v)=(f(u),f(v)(u,v)=(f(u),f(v) 2) Prove that ff is linear.
linear algebralinear algebra unsolved
Geometric Inequality

Source: Iranian National Olympiad (3rd Round) 2006

9/21/2006
In triangle ABCABC, if L,M,NL,M,N are midpoints of AB,AC,BCAB,AC,BC. And HH is orthogonal center of triangle ABCABC, then prove that LH2+MH2+NH214(AB2+AC2+BC2)LH^{2}+MH^{2}+NH^{2}\leq\frac14(AB^{2}+AC^{2}+BC^{2})
inequalitiestrigonometrygeometryincentergeometric transformationreflectioncircumcircle
Countable Zorn Lemma

Source: Iranian National Olympiad (3rd Round) 2006

9/11/2006
Let CC be a (probably infinite) family of subsets of N\mathbb{N} such that for every chain C1C2C_{1}\subset C_{2}\subset \ldots of members of CC, there is a member of CC containing all of them. Show that there is a member of CC such that no other member of CC contains it!
combinatorics proposedcombinatorics
Cantor set in Z

Source: Iranian National Math Olympiad (Final exam) 2006

9/14/2006
For AZA\subset\mathbb Z and a,bZa,b\in\mathbb Z. We define aA+b:={ax+bxA}aA+b: =\{ax+b|x\in A\}. If a0a\neq0 then we calll aA+baA+b and AA to similar sets. In this question the Cantor set CC is the number of non-negative integers that in their base-3 representation there is no 11 digit. You see C=(3C)˙(3C+2)      (1)C=(3C)\dot\cup(3C+2)\ \ \ \ \ \ (1) (i.e. CC is partitioned to sets 3C3C and 3C+23C+2). We give another example C=(3C)˙(9C+6)˙(3C+2)C=(3C)\dot\cup(9C+6)\dot\cup(3C+2). A representation of CC is a partition of CC to some similiar sets. i.e. C=i=1nCi      (2)C=\bigcup_{i=1}^{n}C_{i}\ \ \ \ \ \ (2) and Ci=aiC+biC_{i}=a_{i}C+b_{i} are similar to CC. We call a representation of CC a primitive representation iff union of some of CiC_{i} is not a set similar and not equal to CC. Consider a primitive representation of Cantor set. Prove that a) ai>1a_{i}>1. b) aia_{i} are powers of 3. c) ai>bia_{i}>b_{i} d) (1) is the only primitive representation of CC.
geometrygeometric transformationnumber theory proposednumber theory