MathDB

Problems(1)

Today's calculation of Integral 39

Source: 1990 Tokyo Institute of Technology

6/9/2005
Find the minimum value of the following function f(x)f(x) defined at 0<x<π20<x<\frac{\pi}{2}. f(x)=0xdθcosθ+xπ2dθsinθf(x)=\int_0^x \frac{d\theta}{\cos \theta}+\int_x^{\frac{\pi}{2}} \frac{d\theta}{\sin \theta}
calculusintegrationfunctiontrigonometrylogarithmscalculus computations