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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
110
110
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of integral 110
Source: Kochi University entrance exam/Science 2003
6/7/2006
Prove the following inequality.
1
≤
∫
0
π
2
1
−
sin
3
x
d
x
≤
1
2
{
2
+
ln
(
1
+
2
)
}
1\leq \int_0^{\frac{\pi}{2}} \sqrt{1-\sin ^ 3 x} \ dx\leq \frac{1}{2}\{\sqrt{2}+\ln (1+\sqrt{2}\ ) \}
1
≤
∫
0
2
π
1
−
sin
3
x
d
x
≤
2
1
{
2
+
ln
(
1
+
2
)}
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