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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
140
140
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 140
Source: Kagawa University entrance exam/medical 1998
8/13/2006
Evaluate
∫
0
π
4
(
cos
x
sin
x
+
cos
x
)
2
d
x
,
∫
0
π
4
(
sin
x
+
cos
x
cos
x
)
2
d
x
.
\int_{0}^{\frac{\pi}{4}}\left(\frac{\cos x}{\sin x+\cos x}\right)^{2}\ dx,\ \ \ \int_{0}^{\frac{\pi}{4}}\left(\frac{\sin x+\cos x}{\cos x}\right)^{2}\ dx.
∫
0
4
π
(
sin
x
+
cos
x
cos
x
)
2
d
x
,
∫
0
4
π
(
cos
x
sin
x
+
cos
x
)
2
d
x
.
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