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155

Part of 2006 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 155

Source: Kyoto University entrance exam/science 2000

9/27/2006
The sequence {cn}\{c_{n}\} is determined by the following equation. cn=(n+1)∫01xncos⁡πx dx (n=1, 2, ⋯ ).c_{n}=(n+1)\int_{0}^{1}x^{n}\cos \pi x\ dx\ (n=1,\ 2,\ \cdots). Let λ\lambda be the limit value lim⁡n→∞cn.\lim_{n\to\infty}c_{n}. Find lim⁡n→∞cn+1−λcn−λ.\lim_{n\to\infty}\frac{c_{n+1}-\lambda}{c_{n}-\lambda}.
calculusintegrationtrigonometrylimitcalculus computations