MathDB

285

Part of 2008 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 285

Source: 2008 Jikei University School of Medicine

1/27/2008
Find the minimum value of \int_0^1 \frac{2}{|2t\minus{}x|\plus{}3}\ dt　for 0≤x≤4. 0\leq x\leq 4.
calculusintegrationlogarithmsfunctioncalculus computations