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804

Part of 2012 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 804

Source: 2012 Hokkaido University entrance exam/Science, 2nd exam # 3

3/13/2012
For a>0a>0, find the minimum value of I(a)=∫1e∣ln⁡ax∣ dx.I(a)=\int_1^e |\ln ax|\ dx.
calculusintegrationlogarithmsderivativefunctioncalculus computations