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Today's Calculation Of Integral
2012 Today's Calculation Of Integral
830
830
Part of
2012 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 830
Source: 2012 Tottori University entrance exam/Medicine
7/1/2012
Find
lim
n
→
∞
1
(
ln
n
)
2
∑
k
=
3
n
ln
k
k
.
\lim_{n\to\infty} \frac{1}{(\ln n)^2}\sum_{k=3}^n \frac{\ln k}{k}.
lim
n
→
∞
(
l
n
n
)
2
1
∑
k
=
3
n
k
l
n
k
.
calculus
integration
limit
logarithms
function
calculus computations