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Today's Calculation Of Integral
2012 Today's Calculation Of Integral
845
845
Part of
2012 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 845
Source: 2012 Iwate University entrance exam/Education
9/12/2012
Consider for a real number
t
>
1
t>1
t
>
1
,
I
(
t
)
=
∫
−
4
4
t
−
4
(
x
−
4
)
x
+
4
d
x
.
I(t)=\int_{-4}^{4t-4} (x-4)\sqrt{x+4}\ dx.
I
(
t
)
=
∫
−
4
4
t
−
4
(
x
−
4
)
x
+
4
d
x
.
Find the minimum value of
I
(
t
)
(
t
>
1
)
.
I(t)\ (t>1).
I
(
t
)
(
t
>
1
)
.
calculus
integration
calculus computations