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Today's Calculation Of Integral
2012 Today's Calculation Of Integral
856
856
Part of
2012 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 856
Source:
11/17/2012
On the coordinate plane, find the area of the part enclosed by the curve
C
:
(
a
+
x
)
y
2
=
(
a
−
x
)
x
2
(
x
≥
0
)
C: (a+x)y^2=(a-x)x^2\ (x\geq 0)
C
:
(
a
+
x
)
y
2
=
(
a
−
x
)
x
2
(
x
≥
0
)
for
a
>
0
a>0
a
>
0
.
calculus
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