Let there be a pentagon ABCDE inscribed in a circle O. The tangent to O at E is parallel to AD. A point F lies on O and it is in the opposite side of A with respect to CD, and satisfies AB⋅BC⋅DF=AE⋅ED⋅CF and ∠CFD=2∠BFE. Prove that the tangent to O at B,E and line AF concur at one point. geometryTangentspentagonconcurrencyconcurrent