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Problems
Contests
National and Regional Contests
Lithuania Contests
Grand Duchy of Lithuania
2017 Grand Duchy of Lithuania
2017 Grand Duchy of Lithuania
Part of
Grand Duchy of Lithuania
Subcontests
(4)
1
1
Hide problems
1 < a_n < 1 +1/3^n if a_n =(2a_{n-1} + 1)/(a_{n-1} + 2)
The infinite sequence
a
0
,
a
1
,
a
2
,
a
3
,
.
.
.
a_0, a_1, a_2, a_3,...
a
0
,
a
1
,
a
2
,
a
3
,
...
is defined by
a
0
=
2
a_0 = 2
a
0
=
2
and
a
n
=
2
a
n
−
1
+
1
a
n
−
1
+
2
a_n =\frac{2a_{n-1} + 1}{a_{n-1} + 2}
a
n
=
a
n
−
1
+
2
2
a
n
−
1
+
1
,
n
=
1
,
2
,
3
,
.
.
.
n = 1, 2, 3, ...
n
=
1
,
2
,
3
,
...
Prove that
1
<
a
n
<
1
+
1
3
n
1 < a_n < 1 + \frac{1}{3^n}
1
<
a
n
<
1
+
3
n
1
for all
n
=
1
,
2
,
3
,
.
.
n = 1, 2, 3, . .
n
=
1
,
2
,
3
,
..
4
1
Hide problems
no of distinct odd prime factors of n(n + 3) is a multiple of 3
Show that there are infinitely many positive integers
n
n
n
such that the number of distinct odd prime factors of
n
(
n
+
3
)
n(n + 3)
n
(
n
+
3
)
is a multiple of
3
3
3
.(For instance,
180
=
2
2
⋅
3
2
⋅
5
180 = 2^2 \cdot 3^2 \cdot 5
180
=
2
2
⋅
3
2
⋅
5
has two distinct odd prime factors and
840
=
2
3
⋅
3
⋅
5
⋅
7
840 = 2^3 \cdot 3 \cdot 5 \cdot 7
840
=
2
3
⋅
3
⋅
5
⋅
7
has three.)
2
1
Hide problems
a deck of 52 cards is stacked in a pile facing down
A deck of
52
52
52
cards is stacked in a pile facing down. Tom takes the small pile consisting of the seven cards on the top of the deck, turns it around, and places it at the bottom of the deck. All cards are again in one pile, but not all of them face down, since the seven cards at the bottom now face up. Tom repeats this move until all cards face down again. In total, how many moves did Tom make?
3
1
Hide problems
AC // BM wanted, right triangle, projections, midpoints, circumcenter
Let
A
B
C
ABC
A
BC
be a triangle with
∠
A
=
9
0
o
\angle A = 90^o
∠
A
=
9
0
o
and let
D
D
D
be an orthogonal projection of
A
A
A
onto
B
C
BC
BC
. The midpoints of
A
D
AD
A
D
and
A
C
AC
A
C
are called
E
E
E
and
F
F
F
, respectively. Let
M
M
M
be the circumcentre of
△
B
E
F
\vartriangle BEF
△
BEF
. Prove that
A
C
∥
B
M
AC\parallel BM
A
C
∥
BM
.