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JOM 2023
2
2
Part of
JOM 2023
Problems
(1)
Product of digits
Source: JOM 2023 P2
2/20/2023
Ruby has a non-negative integer
n
n
n
. In each second, Ruby replaces the number she has with the product of all its digits. Prove that Ruby will eventually have a single-digit number or
0
0
0
. (e.g.
86
→
8
×
6
=
48
→
4
×
8
=
32
→
3
×
2
=
6
86\rightarrow 8\times 6=48 \rightarrow 4 \times 8 =32 \rightarrow 3 \times 2=6
86
→
8
×
6
=
48
→
4
×
8
=
32
→
3
×
2
=
6
)Proposed by Wong Jer Ren
algebra