Let ABC be an acuted-angle triangle and let H be it's orthocenter. Let PQ be a segment through H such that P lies on AB and Q lies on AC and such that ∠PHB=∠CHQ. Finally, in the circumcircle of △ABC, consider M such that M is the mid point of the arc BC that doesn't contain A. Prove that MP=MQProposed by Eduardo Velasco/Marco Figueroa circumcirclegeometry proposedgeometry