In a triangle ABC the point D is the intersection of the interior angle bisector of ∠BAC and side BC. Let P be the second intersection point of the exterior angle bisector of ∠BAC with the circumcircle of ∠ABC. A circle through A and P intersects line segment BP internally in E and line segment CP internally in F. Prove that ∠DEP=∠DFP. geometrycircumcircleequal anglesAngle Chasingangle bisector