4
Part of 2018 Dutch IMO TST
Problems(3)
f_1(f_2(y) - x)+ 2x = f_3(x + y) => f(x - f(x))= 0
Source: Dutch IMO TST 2018 day 1 p4
8/30/2019
Let be a set of functions .
For all there exists a such that for all .
Prove that for all , we have for all .
functional equationfunctionalgebra
students in a classroom sit in a round table, possible to split into 3 groups
Source: Dutch IMO TST 2018 day 2 p4
8/30/2019
In the classroom of at least four students the following holds: no matter which four of them take seats around a round table, there is always someone who either knows both of his neighbours, or does not know either of his neighbours. Prove that it is possible to divide the students into two groups such that in one of them, all students know one another, and in the other, none of the students know each other.(Note: if student A knows student B, then student B knows student A as well.)
combinatorics
FN is tangent to the circle through B, I,C, incenter and circumcircle related
Source: Dutch IMO TST3 2018 p4
8/5/2019
In a non-isosceles triangle the centre of the incircle is denoted by . The other intersection point of the angle bisector of and the circumcircle of is . The line through perpendicular to intersects in . The midpoint of the circle arc on which lies, is denoted by . The other intersection point of the line and the circle through and , is denoted by . Prove that is tangent to the circle through and .
circumcircletangentgeometryincenterarc midpoint