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Problems
Contests
National and Regional Contests
Netherlands Contests
Dutch Mathematical Olympiad
1981 Dutch Mathematical Olympiad
1
1
Part of
1981 Dutch Mathematical Olympiad
Problems
(1)
f(x) = [x] + [2x] + [3x] + [4x] + [5x] + [6x]
Source: Netherlands - Dutch NMO 1981 p1
1/28/2023
f
(
x
)
=
[
x
]
+
[
2
x
]
+
[
3
x
]
+
[
4
x
]
+
[
5
x
]
+
[
6
x
]
f(x) = [x] + [2x] + [3x] + [4x] + [5x] + [6x]
f
(
x
)
=
[
x
]
+
[
2
x
]
+
[
3
x
]
+
[
4
x
]
+
[
5
x
]
+
[
6
x
]
. What values does
f
f
f
take?
algebra
floor function