In acute-angled triangle ABC with ∣BC∣<∣BA∣, point N is the midpoint of AC. The circle with diameter AB intersects the bisector of ∠B in two points: B and X. Prove that XN is parallel to BC.
https://cdn.artofproblemsolving.com/attachments/5/1/f0ae8f5df8f2cc1bb80de1ee1807dc845a87b3.png parallelgeometryangle bisector