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National and Regional Contests
Poland Contests
Poland - Second Round
1953 Poland - Second Round
2
2
Part of
1953 Poland - Second Round
Problems
(1)
10 + 11 + 12 + 13 + 14 + 15 + 16 & = & 27 + 64
Source: Polish MO second round 1953 p1
8/29/2024
The board was placed
<
b
r
/
>
1
=
1
<
b
r
/
>
2
+
3
+
4
=
1
+
8
<
b
r
/
>
5
+
6
+
7
+
8
+
9
=
8
+
27
<
b
r
/
>
10
+
11
+
12
+
13
+
14
+
15
+
16
=
27
+
64
<
b
r
/
>
…
<
b
r
/
>
\begin{array}{rcl}<br /> 1 & = & 1 \\<br /> 2 + 3 + 4 & = & 1 + 8 \\<br /> 5 + 6 + 7 + 8 + 9 & = & 8 + 27\\<br /> 10 + 11 + 12 + 13 + 14 + 15 + 16 & = & 27 + 64\\<br /> & \ldots &<br /> \end{array}
<
b
r
/
>
1
<
b
r
/
>
2
+
3
+
4
<
b
r
/
>
5
+
6
+
7
+
8
+
9
<
b
r
/
>
10
+
11
+
12
+
13
+
14
+
15
+
16
<
b
r
/
>
=
=
=
=
…
1
1
+
8
8
+
27
27
+
64
<
b
r
/
>
Write such a formula for the
n
n
n
-th row of the array that, with the substitutions
n
=
1
,
2
,
3
,
4
n = 1, 2, 3, 4
n
=
1
,
2
,
3
,
4
, would give the above four lines of the array and would be true for every natural
n
n
n
.
algebra
Sum