MathDB

1

Part of 1989 Poland - Second Round

Problems(1)

tg 7x - sin 6x=cos 4x - ctg 7x

Source: Polish MO Recond Round 1989 p1

9/9/2024
Solve the equation tg7x−sin⁡6x=cos⁡4x−ctg7x. tg 7x - \sin 6x=\cos 4x - ctg 7x.
algebratrigonometry